Please speak up if you believe your answer is more correct than answers
listed below!

Keys to balancing equations--Do whatever works for you and check your answer for both atom and charge balance.
Acidic solutions--H2O and/or H+ may be added to either side of the equation.
Basic solutions--H2O and/or OH- may be added to either side of the equation.

26
Both NH3 and HC2H3O2 are weak and would not be very conductive alone. However, when mixed together they react together to form a salt. This in turn causes more ionization of the neutral molecules. (You'll spend lots of time next semester discussing chemical equilibria and reversible reactions).

28 5 x 10-5 M NaF

34 (you should know common ions and their charges)
a Ag+ + Cl- = AgCl
b S2- + Fe2+ = FeS
c CO32- + 2 Ag+ = Ag2CO3

40
Na2CrO4 and ZnSO4 will dissolve in H2O (these salts are soluble)
BaCO3 and Al(OH)3 are not water soluble, but H+ from HCl reacts with CO32- and OH-. Neither BaCl2 nor AlCl3 will precipatate because they are both soluble. Sulfuric acid would form BaSO4 ppt, but would be OK for the Al. because Al2(SO4)3 is soluble.

46 (these are probably easier by trial and error)
a 4 NH3 + 5 O2 = 4 NO + 6 H2O
b 5 H2 + 2 NO = 2 NH3 + 2 H2O

48
a 3 P4 + 20 NO3- + 8H2O + 8H+= 12H2PO4- + 20 NO
b 8MnO4- + 5S2O32- + 14H+= 10(SO4)2- + 8 Mn2+ + 7H2O
c 2 HS- + 4 (HSO3)- = 3(S2O3)2- + 3H2O
d 4 Fe3+ + 2 NH3OH+ = 4 Fe2+ + N2O + H2O + 6H+

50
a 6 Cl2 + 12 OH- = 10 Cl- + 2 (ClO3)- + 6 H2O
b 2(S2O4)2- + 1H2O = 2HSO3- + (S2O3)2-
c 3 (MnO4)2- + 2 H2O = 2 MnO4- + MnO2 + 4 OH-
d 4 P4 +12 H2O + 12 OH- = 12 (H2PO2)- + 4 PH3 (or divide thru by 4 to simplify)

58
Each Ba releases 2 OH
14.9mL

70
Equation is balanced for you in summarizing example
130 g Cr(OH)3
329 g Na2S2O4

84
5 As2O3 + 9 H2O + 4 MnO4- + 12 H+ = 10 H3AsO4 + 4 Mn2+
[KMnO4] = 0.02140 M and finally, 24.63 mL solution.