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Chemistry 104 Laboratory |
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This Week |
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Expt 5: pH Titration |
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Next Week |
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Expt
6: Solubility and Thermodynamics á
Quiz 4: Expt 1 |
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Notes for Today |
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e.g., HCl
+ NaOH --> H2O + NaCl
Ka = [H+][A-]/[HA] -log(Ka) =
-log[H+] + {log([A-]/[HA])} pKa = pH -
log([A-]/[HA]) pH = pKa +
log([A-]/[HA] |
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Four Important Regions/Points In
Any HA-NaOH Titration |
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moles NaOH added = moles HA initially present No NaOH, HA remain (rxn complete) Only NaA + water remain
0.0050 mole HA:
HA + NaOH --> H2O + NaA 0.0050 mole HCl:
HCl +
NaOH --> H2O + NaCl |
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