Reactions
Reaction A.
1. Write a list of observations about the reaction in the vial. Use the loupe (magnifying glass) to better see whatÕs going on.
-the solution turns blue
-silver crystals form on the copper
wire beneath the surface of the liquid.
2. Make some hypotheses about what oxidation and reduction reactions took place in vial A.
The white metal looks like
silver. So perhaps Ag+
--> Ag metal
3.Write half reactions for the oxidation and reduction reactions, then a balanced net redox equation for the overall vial reaction.
Cu --> Cu(2+) + 2 e-
[Ag(+)
+ e- --> Ag] x 2
Cu + 2 Ag(+) --> Cu(2+) + 2 Ag
Reaction B.
Observations:
2. Vial B contained an aqueous solution of glucose. During the redox reaction that occurred in the warm water bath, glucose was converted into gluconic acid. The structures of glucose and gluconic acid are shown below.

3. What is the type of redox reaction that produces gluconic acid? To help you figure this out, check out how oxidation states of C and H are assigned in organic molecules below, as the number of oxygen atoms around C increases:

Glucose --> gluconic acid is an oxidation; an O atom from water is added.

Since the O atoms are ALWAYS -2, what is the NET change in oxidation states of C and any H atoms in this half reaction? How many e- are lost or gained?
There are 2 e- lost when glucose --> gluconic acid; the C goes from +2 to +3 and one H goes from 0 to +1.
It appears that a silver mirror formed on the vial walls.
C6H12O6 + 2 Ag(+) + H2O ---> C6H12O7 + 2 Ag(0) + 2H+
7. Adjust your balanced reaction to occur in basic solution, which is the actual condition of the reaction you performed.
... add 2OH- to each side to "neutralize" the H+ (this makes 2 H2O):
C6H12O6 + 2 Ag(+) + 2OH- ---> C6H12O7 + 2 Ag(0) + H2O