Answers to Chapter 7

 

 

Please speak up if you believe your answer is more correct than answers

listed below!

28.

280 Joules

Use your physics to convert L.atm to Joules

36.

797 mL H2O

38.

1.28x10^5 kJ

44. The temperature change is 14 degrees so the final temp. is 10 degrees.

52

-5.65x10^3 kJ/mol C10H14O

56

Delta H = - 284 kJ = -1077 -58.2 - 135.4 +2x296.8 + 393.5

These problems must be done by trial and error.

Pick one reaction which has some reactants and products

which are found in the net reaction. Then add reactions

which eliminate species not found in the final reaction.

60

b is the correct answer because the definitions of the heat of formation of CO2 is the same as the heat of combustion of graphite--C + O2 = CO2.

66

-199 kJ/mol

78

66.36 kJ for 2NO2

82.38 kJ for N2O3 + 1/2O2

82

a CH4 + 2O2 = CO2 + 2H2O

from tables can calculate delta H of the rxn = -890.3kJ

b Heat absorbed by the ice is 3.57 kJ

and using the Gas Laws (which we won't get to until Chap. 6)

we find .004 moles of methane.

From the heat and the number of moles we find -892 kJ/mole methane.